b^2=2b-8

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Solution for b^2=2b-8 equation:


Simplifying
b2 = 2b + -8

Reorder the terms:
b2 = -8 + 2b

Solving
b2 = -8 + 2b

Solving for variable 'b'.

Reorder the terms:
8 + -2b + b2 = -8 + 2b + 8 + -2b

Reorder the terms:
8 + -2b + b2 = -8 + 8 + 2b + -2b

Combine like terms: -8 + 8 = 0
8 + -2b + b2 = 0 + 2b + -2b
8 + -2b + b2 = 2b + -2b

Combine like terms: 2b + -2b = 0
8 + -2b + b2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-8' to each side of the equation.
8 + -2b + -8 + b2 = 0 + -8

Reorder the terms:
8 + -8 + -2b + b2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -2b + b2 = 0 + -8
-2b + b2 = 0 + -8

Combine like terms: 0 + -8 = -8
-2b + b2 = -8

The b term is -2b.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2b + 1 + b2 = -8 + 1

Reorder the terms:
1 + -2b + b2 = -8 + 1

Combine like terms: -8 + 1 = -7
1 + -2b + b2 = -7

Factor a perfect square on the left side:
(b + -1)(b + -1) = -7

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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